3x^2+2x-9.72=0

Solution for 3x^2+2x-9.72=0 equation:

3x^2+2x-9.72=0

a = 3; b = 2; c = -9.72;
Δ = b2-4ac
Δ = 22-4·3·(-9.72)
Δ = 120.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{120.64}}{2*3}=\frac{-2-\sqrt{120.64}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{120.64}}{2*3}=\frac{-2+\sqrt{120.64}}{6}
$